Post by Creator » Wed Mar 17, 2010, 17:50
In the paper, Eq.3 has a mistake:
I_1(x,y) - |b(x,y)|*I_2(x+A(x,y),y)-(1-|b(x,y)|)*I_2(x+A(x,y)+sign(b(x,y)),y) = 0
Must be:
I_1(x,y) - (1-|b(x,y)|)*I_2(x+A(x,y),y)-|b(x,y)|*I_2(x+A(x,y)+sign(b(x,y)),y) = 0
In the paper, Eq.3 has a mistake:
[i][b]I_1(x,y)[/b] - [color=#BF0000]|b(x,y)|[/color]*[b]I_2(x+A(x,y),y)[/b]-[color=#BF0000](1-|b(x,y)|)[/color]*[b]I_2(x+A(x,y)+sign(b(x,y)),y)[/b] = 0[/i]
Must be:
[i][b]I_1(x,y)[/b] - [color=#4000FF](1-|b(x,y)|)[/color]*[b]I_2(x+A(x,y),y)[/b]-[color=#4000FF]|b(x,y)|[/color]*[b]I_2(x+A(x,y)+sign(b(x,y)),y)[/b] = 0[/i]